Sunday, July 31, 2011
Monday, July 11, 2011
Thursday, July 7, 2011
Sunday, July 3, 2011
Same 3 Digit Numbers....!!
Step1:
Think of any 3 digit number,
but each of the digits must be the same as. Ex: 333, 666.
Step2:
Add up the digits.
Step3:
Divide the 3 digit number with the digits added up.
" The number is always 37 "
Think of any 3 digit number,
but each of the digits must be the same as. Ex: 333, 666.
Step2:
Add up the digits.
Step3:
Divide the 3 digit number with the digits added up.
" The number is always 37 "
<<<< Day of the Date >>>>
Remember this table which will help you to calculate :
January 0
February 3
March 3
April 6
May 1
June 4
July 6
August 2
September 5
October 0
November 3
December 5
lets start with my birthday..that is 16th july 1992.
Step1: Ask for the Date. Ex:16th july 1992.
Step2: Number of the month on the list, July is 6.
Step3: Take the date of the month, that is 16
Step4: Take the last 2 digits of the year, that is 92.
Step5: Find out the number of leap years. Divide the last 2 digits of the year by 4, 92 divide by 4 is 23.
Step6: Now add all the 4 numbers: 6 + 16 + 92 + 23 = 137.
Step7: Divide 137 by 7 = 19 remainder 4.
Monday 1
Tuesday 2
Wednesday 3
Thursday 4
Friday 5
Saturday 6
The reminder tells you the day.
Thursday 4
so the answer is Thursday.........!!!!
January 0
February 3
March 3
April 6
May 1
June 4
July 6
August 2
September 5
October 0
November 3
December 5
lets start with my birthday..that is 16th july 1992.
Step1: Ask for the Date. Ex:16th july 1992.
Step2: Number of the month on the list, July is 6.
Step3: Take the date of the month, that is 16
Step4: Take the last 2 digits of the year, that is 92.
Step5: Find out the number of leap years. Divide the last 2 digits of the year by 4, 92 divide by 4 is 23.
Step6: Now add all the 4 numbers: 6 + 16 + 92 + 23 = 137.
Step7: Divide 137 by 7 = 19 remainder 4.
Monday 1
Tuesday 2
Wednesday 3
Thursday 4
Friday 5
Saturday 6
The reminder tells you the day.
Thursday 4
so the answer is Thursday.........!!!!
Divisibility Rules.....!!!
100 - the last 2 digits are 00
25 - the last 2 digits are 00, 25, 50 or 75
10 - the last digit is 0
2 - the last digit is 0, 2, 4, 6 or 8
3 - the sum of the digits is divisible by 3
4 - the last 2 digits are divisible by 4
5 - the last digit is 0 or 5
6 - the number is even and divisible by 3
8 - the last 3 digits are divisible by 8
9 - the sum of the digits is divisible by 9. Saturday, July 2, 2011
Fact of Number 11
suppose take a number between 10-100
then reverse the such as if you take a number 12
then make it as 21
add 11 to the obtained number 21+11=33
it is divisible by 11
for example take 45
then reverse it then it would become 54
add 11 to it then it is 66.....!!!
then reverse the such as if you take a number 12
then make it as 21
add 11 to the obtained number 21+11=33
it is divisible by 11
for example take 45
then reverse it then it would become 54
add 11 to it then it is 66.....!!!
Sum Of Number Series
I have a new trick.
How we find sum of a number series like.
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = ?
So, First take next digit of last number that is 11.
and then take mid digit of series that is 5.
11 * 5 == 55
this is the also the sum of=
1 + 2 + 3 + 4 + 5+ 6 + 7 + 8 + 9 + 10 = 55.....!!
How we find sum of a number series like.
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = ?
So, First take next digit of last number that is 11.
and then take mid digit of series that is 5.
11 * 5 == 55
this is the also the sum of=
1 + 2 + 3 + 4 + 5+ 6 + 7 + 8 + 9 + 10 = 55.....!!
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